化简:cos(θ+π2)sin(θ+3π)sin(θ-π2)cos(θ-2π)tan(θ+π)=______.-数学

题目简介

化简:cos(θ+π2)sin(θ+3π)sin(θ-π2)cos(θ-2π)tan(θ+π)=______.-数学

题目详情

化简:
cos(θ+
π
2
)sin(θ+3π)
sin(θ-
π
2
)cos(θ-2π)tan(θ+π)
=______.
题型:填空题难度:中档来源:不详

答案

cos(θ+class="stub"π
2
)sin(θ+3π)
sin(θ-class="stub"π
2
)cos(θ-2π)tan(θ+π)
=class="stub"sinθsinθ
-cosθcosθtanθ
=class="stub"sinθsinθcosθ
-cosθcosθsinθ
=-tanθ.
故答案为:-tanθ.

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