设f(x)=2x+2(-1≤x<0)-12x(0<x<2)则f(f(f(-34)))的值为______.-数学

题目简介

设f(x)=2x+2(-1≤x<0)-12x(0<x<2)则f(f(f(-34)))的值为______.-数学

题目详情

f(x)=
2x+2(-1≤x<0)
-
1
2
x(0<x<2)
f(f(f(-
3
4
)))
的值为______.
题型:填空题难度:偏易来源:不详

答案

根据所给解析式有f(-class="stub"3
4
)=-class="stub"3
2
+2=class="stub"1
2

所以f(f(-class="stub"3
4
))=f(class="stub"1
2
)=-class="stub"1
4

所以f(f(f(-class="stub"3
4
)))=f(-class="stub"1
4
)=-class="stub"1
2
+2=class="stub"3
2

故答案为:class="stub"3
2

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