设f(x)=|x-1|-2,|x|≤111+x2,|x|>1,则,f(f(12))=______.-数学

题目简介

设f(x)=|x-1|-2,|x|≤111+x2,|x|>1,则,f(f(12))=______.-数学

题目详情

f(x)=
|x-1|-2,|x|≤1
1
1+x2
,|x|>1
,则,f(f(
1
2
))
=______.
题型:填空题难度:偏易来源:南通模拟

答案

∵f(class="stub"1
2
)=|class="stub"1
2
-1
|-2=-class="stub"3
2

f(f(class="stub"1
2
))
=f(-class="stub"3
2
)=class="stub"1
1+(-class="stub"3
2
)
2
=class="stub"4
13

故答案为:class="stub"4
13

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