y=x在点A(1,1)处的切线方程是()A.x-2y+1=0B.2x-y-1=0C.x+2y-3=0D.2x+y-3=0-数学

题目简介

y=x在点A(1,1)处的切线方程是()A.x-2y+1=0B.2x-y-1=0C.x+2y-3=0D.2x+y-3=0-数学

题目详情

y=
x
在点A(1,1)处的切线方程是(  )
A.x-2y+1=0B.2x-y-1=0C.x+2y-3=0D.2x+y-3=0
题型:单选题难度:偏易来源:不详

答案

由题意得,y′=class="stub"1
2
x

∴在点A(1,1)处的切线斜率是class="stub"1
2

则在点A(1,1)处的切线方程为y-1=class="stub"1
2
(x-1),
即x-2y+1=0,
故选A.

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