已知sin(α+3π4)=17,cos(π4-β)=45,且-π4<α<π4,π4<β<3π4,求cos(α-β)的值.-数学

题目简介

已知sin(α+3π4)=17,cos(π4-β)=45,且-π4<α<π4,π4<β<3π4,求cos(α-β)的值.-数学

题目详情

已知sin(α+
4
)=
1
7
cos(
π
4
-β)=
4
5
,且-
π
4
<α<
π
4
π
4
<β<
4
,求cos(α-β)的值.
题型:解答题难度:中档来源:不详

答案

-class="stub"π
4
<α<class="stub"π
4
class="stub"π
4
<β<class="stub"3π
4
,∴class="stub"π
2
<α+class="stub"3π
4
<π
-class="stub"π
2
<class="stub"π
4
-β<0
.…(2分)
又∵sin(α+class="stub"3π
4
)=class="stub"1
7
cos(class="stub"π
4
-β)=class="stub"4
5

cos(α+class="stub"3π
4
)=-
4
3
7
sin(class="stub"π
4
-β)=-class="stub"3
5
.…(6分)
cos(α-β)=-cos(α-β+π)=-cos[(α+class="stub"3π
4
)+(class="stub"π
4
-β)]
=-cos(α+class="stub"3π
4
)cos(class="stub"π
4
-β)+sin(α+class="stub"3π
4
)sin(class="stub"π
4
-β)

=
4
3
7
×class="stub"4
5
+class="stub"1
7
×(-class="stub"3
5
)=
16
3
-3
35
.…(12分)

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