设n∈N*,则Cn1+Cn26+Cn362+…+Cnn6n-1=______.-数学

题目简介

设n∈N*,则Cn1+Cn26+Cn362+…+Cnn6n-1=______.-数学

题目详情

设n∈N*,则Cn1+Cn26+Cn362+…+Cnn6n-1=______.
题型:填空题难度:中档来源:天津

答案

Cn1+Cn26+Cn362+…+Cnn6n-1
=class="stub"1
6
(Cn0+Cn161+Cn262+Cn363+…+Cnn6n-Cn0)
=class="stub"1
6
(Cn0+Cn161+Cn262+Cn363+…+Cnn6n)-class="stub"1
6

=class="stub"1
6
(1+6)n-class="stub"1
6

=class="stub"1
6
7n-class="stub"1
6

=class="stub"1
6
(7n-1)
故答案为class="stub"1
6
(7n-1)

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