∫0-1(x-ex)dx=()A.-32+1eB.-1C.-1-1eD.1-数学

题目简介

∫0-1(x-ex)dx=()A.-32+1eB.-1C.-1-1eD.1-数学

题目详情

0-1
(x-ex)dx
=(  )
A.-
3
2
+
1
e
B.-1C.-1-
1
e
D.1
题型:单选题难度:偏易来源:中山一模

答案

class="stub"1
2
x2-ex
)′=x-ex
0-1
(x-ex)dx
=(class="stub"1
2
x2-ex
)|-10=-1-(class="stub"1
2
-class="stub"1
e
)=-class="stub"3
2
+class="stub"1
e

故选A.

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