设x,y,z∈R+,求证:xy+z+yx+z+zx+y≥32.-数学

题目简介

设x,y,z∈R+,求证:xy+z+yx+z+zx+y≥32.-数学

题目详情

设x,y,z∈R+,求证:
x
y+z
+
y
x+z
+
z
x+y
3
2
题型:解答题难度:中档来源:不详

答案

设S=x+y+z
class="stub"x
y+z
+class="stub"y
x+z
+class="stub"z
x+y

=class="stub"S
y+z
+class="stub"S
x+z
+class="stub"S
x+y
-3
class="stub"9
class="stub"y+z
S
+class="stub"x+z
S
+class="stub"x+y
S
-3
=class="stub"9
2
-3=class="stub"3
2

∴原不等式成立.

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