若等差数列{an}与等比数列{bn}的首项是相等的正数,且它们的第2n+1项也相等,则有()A.an+1<bn+1B.an+1≤bn+1C.an+1≥bn+1D.an+1>bn+1-数学

题目简介

若等差数列{an}与等比数列{bn}的首项是相等的正数,且它们的第2n+1项也相等,则有()A.an+1<bn+1B.an+1≤bn+1C.an+1≥bn+1D.an+1>bn+1-数学

题目详情

若等差数列{an}与等比数列{bn}的首项是相等的正数,且它们的第2n+1项也相等,则有(  )
A.an+1<bn+1B.an+1≤bn+1C.an+1≥bn+1D.an+1>bn+1
题型:单选题难度:偏易来源:不详

答案

因为等差数列{an}和等比数列{bn}各项都是正数,且a1=b1,a2n+1=b2n+1,
所以an+1-bn+1=
a1+a2n+1
2
-
b1b2n+1
=
a1+a2n+1-2
a1a2n+1
2
=
(
a1
-
a2n+1
) 2
2
≥0.
即 an+1≥bn+1.
故选C.

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