先化简,再求值(1)[(x+y)(x-y)-(x+y)2-2y(x-2y)]÷(-2y),其中x=5,y=2003(2)(x-12y-1)(x-12y+1)-(x-12y-1)(x-12),其中x=1

题目简介

先化简,再求值(1)[(x+y)(x-y)-(x+y)2-2y(x-2y)]÷(-2y),其中x=5,y=2003(2)(x-12y-1)(x-12y+1)-(x-12y-1)(x-12),其中x=1

题目详情

先化简,再求值
(1)[(x+y)(x-y)-(x+y)2-2y(x-2y)]÷(-2y),其中x=5,y=2003
(2)(x-
1
2
y-1)(x-
1
2
y+1)-(x-
1
2
y-1)(x-
1
2
)
,其中x=1,y=2.
题型:解答题难度:中档来源:不详

答案

(1)原式=(x2-y2-x2-2xy-y2-2xy+4y2)÷(-2y)=(2y2-4xy)÷(-2y)=-y+2x,
当x=5,y=2003时,原式=-2003+10=-1993;
(2)原式=(x-class="stub"1
2
y)2-1-(x2-class="stub"1
2
x-class="stub"1
2
xy+class="stub"1
4
y-x+class="stub"1
2
)=x2-xy+class="stub"1
4
y2-1-x2+class="stub"1
2
x+class="stub"1
2
xy-class="stub"1
4
y+x-class="stub"1
2
=class="stub"3
2
x-class="stub"1
4
y-class="stub"1
2
xy+class="stub"1
4
y2-class="stub"3
2

当x=1,y=2时,原式=class="stub"3
2
-class="stub"1
2
-1+1-class="stub"3
2
=-class="stub"1
2

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