已知x2+2x-2=0,先将右式化简,再求值:(x-1)2+(x-3)(x+3)-(x-3)(x-1).-数学

题目简介

已知x2+2x-2=0,先将右式化简,再求值:(x-1)2+(x-3)(x+3)-(x-3)(x-1).-数学

题目详情

已知x2+2x-2=0,先将右式化简,再求值:(x-1)2+(x-3)(x+3)-(x-3)(x-1).
题型:解答题难度:中档来源:不详

答案

(x-1)2+(x-3)(x+3)-(x-3)(x-1),
=x2-2x+1+x2-9-x2+4x-3,
=x2+2x-2,
而已知x2+2x-2=0,
则(x-1)2+(x-3)(x+3)-(x-3)(x-1),
=x2+2x-2,
=0.

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