计算:(1)(﹣8a4b5c)÷(4ab5)×(3a3b2)(2)[2(a2x)3﹣9ax5]÷(3ax3)(3)(3mn+1)(﹣1+3mn)﹣(3mn﹣2)2(4)运用整式乘法公式计算1232﹣1

题目简介

计算:(1)(﹣8a4b5c)÷(4ab5)×(3a3b2)(2)[2(a2x)3﹣9ax5]÷(3ax3)(3)(3mn+1)(﹣1+3mn)﹣(3mn﹣2)2(4)运用整式乘法公式计算1232﹣1

题目详情

计算:
(1)(﹣8a4b5c)÷(4ab5)×(3a3b2
(2)[2(a2x)3﹣9ax5]÷(3ax3
(3)(3mn+1)(﹣1+3mn)﹣(3mn﹣2)2
(4)运用整式乘法公式计算1232﹣124×122
(5)[(xy+2)(xy﹣2)﹣2x2y2+4]÷(xy),其中x=10,y=﹣
题型:计算题难度:中档来源:贵州省月考题

答案

解:(1)(﹣8a4b5c)÷(4ab5)×(3a3b2),
=﹣2a3c×(3a3b2),
=﹣6a6b2c;
(2)[2(a2x)3﹣9ax5]÷(3ax3),
=[2a6x3﹣9ax5]÷(3ax3),
=
(3)(3mn+1)(﹣1+3mn)﹣(3mn﹣2)2,
=(9m2n2﹣1)﹣(9m2n2﹣12mn+4),
=9m2n2﹣1﹣9m2n2+12mn﹣4,
=12mn﹣5;
(4)1232﹣124×122,
=1232﹣(123+1)×(123﹣1),
=1232﹣(1232﹣1),
=1232﹣1232+1,
=1;
(5)[(xy+2)(xy﹣2)﹣2x2y2+4]÷(xy),
=[x2y2﹣4﹣2x2y2+4]÷(xy),
=(﹣x2y2)÷(xy),
=﹣xy;
当x=10,y=﹣时,原式=﹣10×(﹣)=

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