C2n2+C2n4+…+C2n2k+…+C2n2n的值为()A.2nB.22n-1C.2n-1D.22n-1-1-数学

题目简介

C2n2+C2n4+…+C2n2k+…+C2n2n的值为()A.2nB.22n-1C.2n-1D.22n-1-1-数学

题目详情

C2n2+C2n4+…+C2n2k+…+C2n2n的值为(  )
A.2nB.22n-1C.2n-1D.22n-1-1
题型:单选题难度:偏易来源:卢湾区一模

答案

由于C2n0+C2n2+C2n4+…+C2n2k+…+C2n2n =22n-1,C2n0=1,
故C2n2+C2n4+…+C2n2k+…+C2n2n =22n-1 -1,
故选:D.

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