数列{an}满足an+an+1=12(n∈N*),a1=-12,Sn是{an}的前n项和,则S2011=______.-数学

题目简介

数列{an}满足an+an+1=12(n∈N*),a1=-12,Sn是{an}的前n项和,则S2011=______.-数学

题目详情

数列{an}满足an+an+1=
1
2
(n∈N*),a1=-
1
2
,Sn是{an}的前n项和,则S2011=______.
题型:填空题难度:中档来源:东城区模拟

答案

an+an+1=class="stub"1
2
(n∈N*),a1=-class="stub"1
2

S2011=a1+(a2+a3)+(a4+a5)+…+(a2010+a2011)
=-class="stub"1
2
+class="stub"1
2
+…+class="stub"1
2

=-class="stub"1
2
+class="stub"1
2
×1005

=502
故答案为:502

更多内容推荐