已知f(α)=sin(5π-α)•cos(α+3π2)•cos(π+α)sin(α-3π2)•cos(α+π2)•tan(α-3π)(1)化简f(α)(2)若α是第三象限角,且cos(3π2-α)=1

题目简介

已知f(α)=sin(5π-α)•cos(α+3π2)•cos(π+α)sin(α-3π2)•cos(α+π2)•tan(α-3π)(1)化简f(α)(2)若α是第三象限角,且cos(3π2-α)=1

题目详情

已知f(α)=
sin(5π-α)•cos(α+
2
)•cos(π+α)
sin(α-
2
)•cos(α+
π
2
)•tan(α-3π)

(1)化简f(α)
(2)若α是第三象限角,且cos(
2
-α)=
1
5
,求f(α)的值.
题型:解答题难度:中档来源:不详

答案

(1)f(α)=
sin(5π-α)•cos(α+class="stub"3π
2
)•cos(π+α)
sin(α-class="stub"3π
2
)•cos(α+class="stub"π
2
)•tan(α-3π)
=
sinα•sinα•(-cosα)
cosα•(-sinα)•tanα
=cosα.
(2)∵cos(class="stub"3π
2
-α)=-sinα=class="stub"1
5
,∴sinα=-class="stub"1
5

又∵α为第三象限角,∴cosα=-
2
6
5
,∴f(α)=-
2
6
5

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