如图,点O是△ABC的内切圆的圆心.若∠BAC=75°,则∠BOC的度数为()A.105°B.125°C.127.5°D.100°-数学

题目简介

如图,点O是△ABC的内切圆的圆心.若∠BAC=75°,则∠BOC的度数为()A.105°B.125°C.127.5°D.100°-数学

题目详情

如图,点O是△ABC的内切圆的圆心.若∠BAC=75°,则∠BOC的度数为(  )
A.105°B.125°C.127.5°D.100°

题型:单选题难度:中档来源:不详

答案

∵点O是△ABC的内切圆的圆心,
∴∠OBC=class="stub"1
2
∠ABC,∠OCB=class="stub"1
2
∠ACB,
∵∠BAC=75°,
∴∠ABC+∠ACB=180°-∠BAC=105°,
∴∠BOC=180°-(∠OBC+∠OCB)=180°-class="stub"1
2
(∠ABC+∠ACB)=180°-class="stub"1
2
×105°=127.5°.
故选C.

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