等差数列{an}中,若a1=1,a8=15,则1a1•a2+1a2•a3+…+1a100•a101=()A.200199B.100199C.200201D.100201-数学

题目简介

等差数列{an}中,若a1=1,a8=15,则1a1•a2+1a2•a3+…+1a100•a101=()A.200199B.100199C.200201D.100201-数学

题目详情

等差数列{an}中,若a1=1,a8=15,则
1
a1a2
+
1
a2a3
+
+
1
a100a101
=(  )
A.
200
199
B.
100
199
C.
200
201
D.
100
201
题型:单选题难度:中档来源:不详

答案

设等差数列的公差为d,
∵a1=1,a8=15,
∴a8=a1+7d=15,
解得d=2,
∴等差数列的通项公式an=2n-1,
class="stub"1
anan+1
=class="stub"1
(2n-1)(2n+1)
=class="stub"1
2
class="stub"1
2n-1
-class="stub"1
2n+1
),
class="stub"1
a1a2
+class="stub"1
a2a3
+
…+class="stub"1
a100a101
=class="stub"1
2
(1-class="stub"1
201
)=class="stub"100
201

故选D.

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