设定义在实数集上函数f(x)满足:f(x+1)+f(-x-1)=0,f(x+2)=f(-x),且当0≤x≤1时,f(x)=3x-1,则有()A.f(73)<f(-32)<f(94)B.f(94)<f(

题目简介

设定义在实数集上函数f(x)满足:f(x+1)+f(-x-1)=0,f(x+2)=f(-x),且当0≤x≤1时,f(x)=3x-1,则有()A.f(73)<f(-32)<f(94)B.f(94)<f(

题目详情

设定义在实数集上函数f(x)满足:f(x+1)+f(-x-1)=0,f(x+2)=f(-x),且当0≤x≤1时,f(x)=3x-1,则有(  )
A.f(
7
3
)<f(-
3
2
)<f(
9
4
)
B.f(
9
4
)<f(-
3
2
)<f(
7
3
)
C.f(
7
3
)<f(
9
4
)<f(-
3
2
)
D.f(-
3
2
)<f(
7
3
)<f(
9
4
)
题型:单选题难度:偏易来源:不详

答案

∵f(x+1)+f(-x-1)=0,f(x+2)=f(-x),
f(-class="stub"3
2
)
=-f(class="stub"3
2
)
=-f(class="stub"1
2
)
=1-3class="stub"1
2
=1-
3

f(class="stub"7
3
)
=f(-class="stub"1
3
)
=-f(class="stub"1
3
)
=1-3class="stub"1
3
=1-
33

f(class="stub"9
4
)
=f(-class="stub"1
4
)
=-f(class="stub"1
4
)
=1-3class="stub"1
4
=1-
43

class="stub"1
2
class="stub"1
3
class="stub"1
4
,函数y=3x为增函数,
3class="stub"1
2
3class="stub"1
3
3class="stub"1
4

故1-3class="stub"1
2
<1-3class="stub"1
3
<1-3class="stub"1
4

f(-class="stub"3
2
)<f(class="stub"7
3
)<f(class="stub"9
4
)

故选D

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