数列1×4,2×5,3×6,…,n×(n+3),…则它的前n项和Sn=______.-数学

题目简介

数列1×4,2×5,3×6,…,n×(n+3),…则它的前n项和Sn=______.-数学

题目详情

数列1×4,2×5,3×6,…,n×(n+3),…则它的前n项和Sn=______.
题型:填空题难度:中档来源:不详

答案

∵an=n×(n+3)=n2+3n,
∴Sn=a1+a2+a3+…+an
=(1+3×1)+(4+3×2)+(9+3×3)+…+(n2+3n)
=(12+22+32+…+n2)+3(1+2+3+…+n)
=
n(n+1)(2n+1)
6
+
3n(n+1)
2

=
n(n+1)(n+5)
3

答案:
n(n+1)(n+5)
3

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