设f(x)=|x-1|-2,|x|≤111+x2,|x|>1.,则f[f(13)]=______.-数学

题目简介

设f(x)=|x-1|-2,|x|≤111+x2,|x|>1.,则f[f(13)]=______.-数学

题目详情

f(x)=
|x-1|-2,|x|≤1
1
1+x2
,|x|>1.
,则f[f(
1
3
)]
=______.
题型:填空题难度:中档来源:不详

答案

f(class="stub"1
3
)=|class="stub"1
3
-1|-2=-class="stub"4
3

f(-class="stub"4
3
)=class="stub"1
1+(-class="stub"4
3
)2
=class="stub"9
25

所以f[f(class="stub"1
3
)]
=f(-class="stub"4
3
)=class="stub"9
25

故答案为:class="stub"9
25

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