设f(x)=2x(x≥0)f(x+1)(x<0),则f(-32)=()A.34B.22C.2D.-12-数学

题目简介

设f(x)=2x(x≥0)f(x+1)(x<0),则f(-32)=()A.34B.22C.2D.-12-数学

题目详情

f(x)=
2x(x≥0)
f(x+1)(x<0)
,则f(-
3
2
)
=(  )
A.
34
B.2
2
C.
2
D.-
1
2
题型:单选题难度:偏易来源:不详

答案

因为f(x)=
2x(x≥0)
f(x+1)(x<0)
,则f(-class="stub"3
2
)
=f(-class="stub"3
2
+1)=f(-class="stub"1
2
)=f(1-class="stub"1
2
)=f(class="stub"1
2
)=2class="stub"1
2
=
2

故选C.

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