等差数列{an}和{bn}中,a1+b100=100,b1+a100=100,则数列{an+bn}的前100项之和为()A.0B.100C.1000D.10000-数学

题目简介

等差数列{an}和{bn}中,a1+b100=100,b1+a100=100,则数列{an+bn}的前100项之和为()A.0B.100C.1000D.10000-数学

题目详情

等差数列{an}和{bn}中,a1+b100=100,b1+a100=100,则数列{an+bn}的前100项之和为(  )
A.0B.100C.1000D.10000
题型:单选题难度:偏易来源:不详

答案

∵{an}、{bn}都是等差数列,
∴{an+bn}是等差数列,
∵a1+b100=100,b1+a100=100,
∴a1+b1+a100+b100=200,
∴S100=
100(a1+b1+a100+b100)   
2
=class="stub"100×200
2
=10000,
故选D.

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