先化简再求值:3(y+1)2-5(y+1)(y-1)+2(y-1)2,其中y=-12.-数学

题目简介

先化简再求值:3(y+1)2-5(y+1)(y-1)+2(y-1)2,其中y=-12.-数学

题目详情

先化简再求值:3(y+1)2-5(y+1)(y-1)+2(y-1)2,其中y=-
1
2
题型:解答题难度:中档来源:不详

答案

3(y+1)2-5(y+1)(y-1)+2(y-1)2
=3(y+1)2-3(y+1)(y-1)+2(y-1)2-2(y+1)(y-1)
=3(y+1)(y+1-y+1)+2(y-1)(y-1-y-1)
=6(y+1)-4(y-1)
=6y+6-4y+4
=2y+10,
当y=-class="stub"1
2
时,
原式=2×(-class="stub"1
2
)+10=9.

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