在△ABC中,记BC=a,CA=b,AB=c,若9a2+9b2-19c2=0,则cotCcotA+cotB=______.-数学

题目简介

在△ABC中,记BC=a,CA=b,AB=c,若9a2+9b2-19c2=0,则cotCcotA+cotB=______.-数学

题目详情

在△ABC 中,记 BC=a,CA=b,AB=c,若9a2+9b2-19c2=0,则
cotC
cotA+cotB
=______.
题型:填空题难度:中档来源:不详

答案

∵9a2+9b2-19c2=0,
∴9a2+9b2=19c2,
class="stub"a
sinA
=class="stub"b
sinB
=class="stub"c
sinC
,cosC=
a2+b2-c2
2ab

class="stub"cotC
cotA+cotB
=
class="stub"cosC
sinC
class="stub"cosA
sinA
+class="stub"cosB
sinB
=
class="stub"cosC
sinC
class="stub"sinBcosC+cosBsinC
sinAsinB
=class="stub"sinAsinB
sin2C
•cosC
=class="stub"ab
c2
a2+b2-c2
2ab
=
a2+b2-c2
2c2
=
9a2+9b2-9c2
2×9c2
=
19c2-9c2
18c2
=class="stub"5
9

故答案为:class="stub"5
9

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