函数y=sin(2x+π3)+cos(2x+π6)的最小正周期T=______-数学

题目简介

函数y=sin(2x+π3)+cos(2x+π6)的最小正周期T=______-数学

题目详情

函数y=sin(2x+
π
3
)+cos(2x+
π
6
)的最小正周期T=______
题型:填空题难度:中档来源:嘉定区二模

答案

y=sin(2x+class="stub"π
3
)+cos(2x+class="stub"π
6
)=sin(2x+class="stub"π
3
)+sin(class="stub"π
2
+2x+class="stub"π
6
)=sin(2x+class="stub"π
3
)+sin(2x+class="stub"2π
3
)=2cos2xcos(-class="stub"π
3
)=cos2x
∴最小正周期T=class="stub"2π
2
=π,
故答案为π

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