设x=11241,y=-4153,求(x+y)2-(x-y)2的值.-数学

题目简介

设x=11241,y=-4153,求(x+y)2-(x-y)2的值.-数学

题目详情

x=1
12
41
,y=-
41
53
,求(x+y)2-(x-y)2的值.
题型:解答题难度:中档来源:不详

答案

解法1:(x+y)2-(x-y)2
=(x2+2xy+y2)-(x2-2xy+y2)
=x2+2xy+y2-x2+2xy-y2
=4xy;
解法2:(x+y)2-(x-y)2
=[(x+y)+(x-y)][(x+y)-(x-y)]
=(x+y+x-y)(x+y-x+y)
=2x•2y
=4xy.
x=1class="stub"12
41
,y=-class="stub"41
53
时,原式=4xy=4×class="stub"53
41
×(-class="stub"41
53
)=-4.

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