设g(x)=1-2x,f(g(x))=1-x2x2(x≠0),则f(12)=______.-数学

题目简介

设g(x)=1-2x,f(g(x))=1-x2x2(x≠0),则f(12)=______.-数学

题目详情

g(x)=1-2x,f(g(x))=
1-x2
x2
(x≠0)
,则f(
1
2
)
=______.
题型:填空题难度:中档来源:不详

答案

令1-2x=class="stub"1
2
解得x=class="stub"1
4

∴f(class="stub"1
2
)=f(1-2×class="stub"1
4
)=f(g(class="stub"1
4
))=
1-(class="stub"1
4
)
2
(class="stub"1
4
)
2
=
class="stub"15
16
class="stub"1
16
=15.
故答案为:15.

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