计算:(1)-327-(3-1)3+225-625(2)(3a2y2)3÷2(-a3y3)2(3)x(x2+x+1)-(x+3)(x-4)(4)(x-2y)(x+2y)-(x-2y)2.-数学

题目简介

计算:(1)-327-(3-1)3+225-625(2)(3a2y2)3÷2(-a3y3)2(3)x(x2+x+1)-(x+3)(x-4)(4)(x-2y)(x+2y)-(x-2y)2.-数学

题目详情

计算:
(1)-
327
-(
3-1
)
3
+
225
-
625

(2)(3a2y23÷2(-a3y32
(3)x(x2+x+1)-(x+3)(x-4)
(4)(x-2y)(x+2y)-(x-2y)2
题型:解答题难度:中档来源:不详

答案

(1)原式=-3-(-1)+15-25=-3+1+15-25=-12;
(2)原式=27(a2)3•(y2)3÷2(-a3)2•(y3)2=27a6y6÷2a6y6=class="stub"27
2

(3)原式=(x3+x2+x)-(x2-4x+3x-12)=x3+x2+x-x2+4x-3x+12=x3+2x+12;
(4)原式=(x2-4y2)-(x2-4xy+4y2)=x2-4y2-x2+4xy-4y2=4xy-8y2.

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