(1)计算:(a+3)2-a(4+a)(2)计算:(8a3b-5a2b2)÷4ab(3)先化简,再求值.[(x+2y)2-(x+y)(3x-y)-5y2]÷2x,其中x=-2,y=12.(4)已知a+

题目简介

(1)计算:(a+3)2-a(4+a)(2)计算:(8a3b-5a2b2)÷4ab(3)先化简,再求值.[(x+2y)2-(x+y)(3x-y)-5y2]÷2x,其中x=-2,y=12.(4)已知a+

题目详情

(1)计算:(a+3)2-a(4+a)
(2)计算:(8a3b-5a2b2)÷4ab
(3)先化简,再求值.[(x+2y)2-(x+y)(3x-y)-5y2]÷2x,其中x=-2,y=
1
2

(4)已知a+b=6,ab=2.①求a2+b2的值;②求(a-b)2的值.
题型:解答题难度:中档来源:不详

答案

(1)原式=a2+6a+9-4a-a2
=2a+9;

(2)原式=8a3b÷4ab-5a2b2÷4ab
=2a2-class="stub"5
4
ab;

(3)[(x+2y)2-(x+y)(3x-y)-5y2]÷2x
=[x2+4xy+4y2-3x2+xy-3xy+y2-5y2]÷2x
=[-2x2+2xy]÷2x
=-x+y,
当x=-2,y=class="stub"1
2
时,原式=-(-2)+class="stub"1
2
=2class="stub"1
2


(4)∵a+b=6,ab=2,
∴①a2+b2=(a+b)2-2ab=62-2×2=32;
②(a-b)2=(a+b)2-4ab=62-4×2=28.

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