计算:(1)x2x-1-x-1(2)x2+2xx2-4-2x-2(3)(xx+1-3xx-1)÷xx2-1(4)(1+2ba-b)2•(12ba+b)2.-数学

题目简介

计算:(1)x2x-1-x-1(2)x2+2xx2-4-2x-2(3)(xx+1-3xx-1)÷xx2-1(4)(1+2ba-b)2•(12ba+b)2.-数学

题目详情

计算:
(1)
x2
x-1
-x-1

(2)
x2+2x
x2-4
-
2
x-2

(3)(
x
x+1
-
3x
x-1
)÷
x
x2-1

(4)(1+
2b
a-b
)
2
(1
2b
a+b
)
2
题型:解答题难度:中档来源:不详

答案

(1)原式=
x2
x-1
-class="stub"x+1
1

=
x2-(x+1)(x-1)
x-1

=class="stub"1
x-1


(2)原式=
x(x+2)
(x+2)(x-2)
-class="stub"2
x-2

=class="stub"x
x-2
-class="stub"2
x-2

=class="stub"x-2
x-2

=1.

(3)原式=
x(x-1)-3x(x+1)
(x+1)(x-1)
(x+1)(x-1)
x

=
-2x2-4x
x

=-2x-4.

(4)原式=(class="stub"a-b+2b
a-b
)2•(class="stub"a+3b
a+b
)2
=
(a+b)2
(a-b)2
(a+3b)2
(a+b)2

=
(a+3b)2
(a-b)2

=
a2+6ab+9b2
a2-2ab+b2

更多内容推荐