计算：．-八年级数学

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• 如果用换元法解方程x2-1x-3xx2-1+2=0，设y=x2-1x，那么原方程可化为（）A．y2-3y+2=0B．y2+3y-2=0C．y2-2y+3=0D．y2+2y-3=0-数学
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• 用换元法解方程(xx+2)2-5(xx+2)+6=0-数学
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• 已知，则的值为（）A．B．C．2D．-八年级数学
• 下列方程不是整式方程的是（）A．22x2-12x=1B．0.2x2-0.4x3=0C．x2+15=3D．1x2+x=2-数学
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• 解方程：x2-2x-2=3x2-2x-数学
• 关于x的方程x2-（5k+1）x+k2-2=0，是否存在负数k，使方程的两个实数根的倒数和等于4？若存在，求出满足条件的k的值；若不存在，说明理由．-数学
• 解方程：x2=6x2-x+x-1-数学
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• 解方程（组）：（1）13(x-1)2=3；（2）2x2-4x-1=0；（3）6x2-x-12=0；（4）x2-6x-391=0；（5）x2+x+2=3x2+x；（6）解方程组：x2+y2=102x-y
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