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题目简介
解方程:x2-2x-2=3x2-2x-数学
题目详情
答案
原方程化为u-2=
两边同乘以u,并整理,得
u2-2u-3=0,
(u-3)(u+1)=0,
∴u1=3,u2=-1.
当u1=3时,x2-2x-3=0,x1=3,x2=-1;
当u2=-1时,x2-2x+1=0,x3,4=1.
经检验:xl=3,x2=-1,x3,4=1都是原方程的根.