先化简，再求值：，其中．-一年级数学

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• (10分)先化简，再求值：，其中．-八年级数学
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• 解方程：x+1-3x+1=2．-数学
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• 用换元法解方程：x+1x-xx+1=32-数学
• 解方程：1x+1+1x-1=0．-数学
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• 若分式的值为0，则x的值为．-八年级数学
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• 解方程：1x-1+x2-3xx2-1=-2．-数学
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• 解方程：3x-2=2-xx-2-数学
• 计算：．-八年级数学
• 计算：．-八年级数学
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• (-xy3)2的计算结果是：()A．xy5B．x2y6C．-x2y6D．x2y5-八年级数学
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• 用换元法解方程(xx+2)2-5(xx+2)+6=0-数学
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• 已知，则的值为（）A．B．C．2D．-八年级数学
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• 解方程：x2-2x-2=3x2-2x-数学
• 关于x的方程x2-（5k+1）x+k2-2=0，是否存在负数k，使方程的两个实数根的倒数和等于4？若存在，求出满足条件的k的值；若不存在，说明理由．-数学
• 解方程：x2=6x2-x+x-1-数学
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• 若解分式方程2xx+1-x+1x=a-1x2+x产生增根，则a的值为（）A．-1或2B．1或2C．0或3D．0或-3-数学