14tan245°+1sin230°-3cos230°+tan45°cos0°-sin40°cos50°.-数学

题目简介

14tan245°+1sin230°-3cos230°+tan45°cos0°-sin40°cos50°.-数学

题目详情

1
4
tan245°+
1
sin230°
-3cos230°+
tan45°
cos0°
-
sin40°
cos50°
题型:解答题难度:中档来源:不详

答案

原式=class="stub"1
4
×12+class="stub"1
(class="stub"1
2
)
2
-3×(
3
2
)2+1-class="stub"sin40°
sin40°

=class="stub"1
4
+4-class="stub"9
4
+1-1
=2.

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