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> 计算下列各题.(1)3x-61-x-x+5x2-x(2)(x2-1)(1x-1-1x+1-1)(3)1x+1-x-3x2-1-x2-2x+1(x-1)(x-3)(4)3-x2x-4÷(x+2-5x-2
计算下列各题.(1)3x-61-x-x+5x2-x(2)(x2-1)(1x-1-1x+1-1)(3)1x+1-x-3x2-1-x2-2x+1(x-1)(x-3)(4)3-x2x-4÷(x+2-5x-2
题目简介
计算下列各题.(1)3x-61-x-x+5x2-x(2)(x2-1)(1x-1-1x+1-1)(3)1x+1-x-3x2-1-x2-2x+1(x-1)(x-3)(4)3-x2x-4÷(x+2-5x-2
题目详情
计算下列各题.
(1)
3
x
-
6
1-x
-
x+5
x
2
-x
(2)
(
x
2
-1)(
1
x-1
-
1
x+1
-1)
(3)
1
x+1
-
x-3
x
2
-1
-
x
2
-2x+1
(x-1)(x-3)
(4)
3-x
2x-4
÷(x+2-
5
x-2
)
(5)
(1-
a-b
a-2b
)÷
a
2
-4
b
2
a
2
-4ab+4
b
2
.
题型:解答题
难度:中档
来源:不详
答案
(1)原式=
3(x-1)
x(x-1)
+
class="stub"6x
x(x-1)
-
class="stub"x+5
x(x-1)
,
=
8(x-1)
x(x-1)
,
=
class="stub"8
x
.
(2)原式=(x+1)(x-1)(
class="stub"x+1
(x+1)(x-1)
-
class="stub"x-1
(x+1)(x-1)
-
(x+1)(x-1)
(x+1)(x-1)
),
=x+1-x+1-(x+1)(x-1),
=-x2+3.
(3)原式=
class="stub"1
x+1
-
class="stub"x-3
(x+1)(x-1)
×
(x-1
)
2
(x-1)(x-3)
,
=
class="stub"1
x+1
-
class="stub"1
x-1
,
=0.
(4)原式=
class="stub"3-x
2(x-2)
÷(
(x+2)(x-2)
x-2
-
class="stub"5
x-2
),
=
class="stub"1
2(x+3)
.
(5)原式=(
class="stub"a-2b
a-2b
-
class="stub"a-b
a-2b
)÷
(a+2b)(a-2b)
(a-2b)
2
,
=
class="stub"-b
a-2b
×
(a-2b)
2
(a+2b)(a-2b)
,
=
-
class="stub"b
a+2b
.
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题目简介
计算下列各题.(1)3x-61-x-x+5x2-x(2)(x2-1)(1x-1-1x+1-1)(3)1x+1-x-3x2-1-x2-2x+1(x-1)(x-3)(4)3-x2x-4÷(x+2-5x-2
题目详情
(1)
(2)(x2-1)(
(3)
(4)
(5)(1-
答案
=
=
(2)原式=(x+1)(x-1)(
=x+1-x+1-(x+1)(x-1),
=-x2+3.
(3)原式=
=
=0.
(4)原式=
=
(5)原式=(
=
=-