计算:(1)2aa2-4+12-a(2)4+(2008)0-(13)-1+|-2|(3)a2a-1-a-1(4)(xx-y-2yx-y)•xyx-2y÷(1x+1y).-数学

题目简介

计算:(1)2aa2-4+12-a(2)4+(2008)0-(13)-1+|-2|(3)a2a-1-a-1(4)(xx-y-2yx-y)•xyx-2y÷(1x+1y).-数学

题目详情

计算:
(1)
2a
a2-4
+
1
2-a
          
(2)
4
+(2008)0-(
1
3
)-1+|-2|

(3)
a2
a-1
-a-1
                  
(4)(
x
x-y
-
2y
x-y
)•
xy
x-2y
÷(
1
x
+
1
y
)
题型:解答题难度:中档来源:不详

答案

(1)原式=class="stub"2a
(a+2)(a-2)
-class="stub"a+2
(a+2)(a-2)
=class="stub"a-2
(a+2)(a-2)
=class="stub"1
a+2

(2)原式=2+1-3+2=2;
(3)原式=
a2-(a+1)(a-1)
a-1
=class="stub"1
a-1

(4)原式=class="stub"x-2y
x-y
class="stub"xy
x-2y
class="stub"xy
x+y
=
x2y2
x2-y2

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