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> 某商场计划购进一批甲、乙两种玩具,已知一件甲种玩具的进价与一件乙种玩具的进价的和为40元,用90元购进甲种玩具的件数与用150元购进乙种玩具的件数相同。(1)求每件甲种、乙-九年级数学
某商场计划购进一批甲、乙两种玩具,已知一件甲种玩具的进价与一件乙种玩具的进价的和为40元,用90元购进甲种玩具的件数与用150元购进乙种玩具的件数相同。(1)求每件甲种、乙-九年级数学
题目简介
某商场计划购进一批甲、乙两种玩具,已知一件甲种玩具的进价与一件乙种玩具的进价的和为40元,用90元购进甲种玩具的件数与用150元购进乙种玩具的件数相同。(1)求每件甲种、乙-九年级数学
题目详情
某商场计划购进一批甲、乙两种玩具,已知一件甲种玩具的进价与一件乙种玩具的进价的和为40元,用90元购进甲种玩具的件数与用150元购进乙种玩具的件数相同。
(1)求每件甲种、乙种玩具的进价分别是多少元?
(2)商场计划购进甲、乙两种玩具共48件,其中甲种玩具的件数少于乙种玩具的件数,商场决定此次进货的总资金不超过1000元,求商场共有几种进货方案?
题型:解答题
难度:偏难
来源:辽宁省中考真题
答案
解:(1)设甲种玩具进价x元/件,则乙种玩具进价为(40-x)元/件,
,
x=15
经检验x=15是原方程的解,
∴40-x=25,
甲,乙两种玩具分别是15元/件,25元/件;
(2)设购进甲种玩具y件,则购进乙种玩具(48-y)件,
解得
,
因为y是整数,所以y取20,21,22,23,共有四种方案。
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题目简介
某商场计划购进一批甲、乙两种玩具,已知一件甲种玩具的进价与一件乙种玩具的进价的和为40元,用90元购进甲种玩具的件数与用150元购进乙种玩具的件数相同。(1)求每件甲种、乙-九年级数学
题目详情
(1)求每件甲种、乙种玩具的进价分别是多少元?
(2)商场计划购进甲、乙两种玩具共48件,其中甲种玩具的件数少于乙种玩具的件数,商场决定此次进货的总资金不超过1000元,求商场共有几种进货方案?
答案
x=15
经检验x=15是原方程的解,
∴40-x=25,
甲,乙两种玩具分别是15元/件,25元/件;
(2)设购进甲种玩具y件,则购进乙种玩具(48-y)件,
解得
因为y是整数,所以y取20,21,22,23,共有四种方案。