式子12(x2-2y)+13(x-y2)-16(x2+y2)=______.-数学

题目简介

式子12(x2-2y)+13(x-y2)-16(x2+y2)=______.-数学

题目详情

式子
1
2
(x2-2y)+
1
3
(x-y2)-
1
6
(x2+y2)=______.
题型:填空题难度:中档来源:不详

答案

原式=class="stub"1
2
x2-y+class="stub"1
3
x-class="stub"1
3
y2-class="stub"1
6
x2-class="stub"1
6
y2=class="stub"1
3
x2-class="stub"1
2
y2-y+class="stub"1
3
x
故应该填:class="stub"1
3
x2-class="stub"1
2
y2-y+class="stub"1
3
x.

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