先化简,再求值:当x=2,y=-1时,求xy2x2-y2-x4yx4-y4÷x2x2+y2的值.-数学

题目简介

先化简,再求值:当x=2,y=-1时,求xy2x2-y2-x4yx4-y4÷x2x2+y2的值.-数学

题目详情

先化简,再求值:当x=2,y=-1时,求
xy2
x2-y2
-
x4y
x4-y4
÷
x2
x2+y2
的值.
题型:解答题难度:中档来源:不详

答案

原式=
xy2
x2-y2
-
x4y
(x2-y2)•(x2+y2)
x2+y2
x2

=
xy2
x2-y2
-
x2y
x2-y2

=
xy2-x2y
x2-y2

=
xy(y-x)
(x-y)(x+y)

=-class="stub"xy
x+y

原式=-
2×(-1)
2+(-1)
=2.

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