计算:(1)﹣12+15﹣|﹣7﹣8|(2)(﹣3)×(﹣9)﹣(﹣5)(3)(4)1÷(﹣3)×(﹣)(5)(6)(7)(x2+2xy+y2)﹣(x2﹣xy+y2)(8)9a2﹣[7a2﹣2a﹣2(

题目简介

计算:(1)﹣12+15﹣|﹣7﹣8|(2)(﹣3)×(﹣9)﹣(﹣5)(3)(4)1÷(﹣3)×(﹣)(5)(6)(7)(x2+2xy+y2)﹣(x2﹣xy+y2)(8)9a2﹣[7a2﹣2a﹣2(

题目详情

计算:(1)﹣12+15﹣|﹣7﹣8|
(2)(﹣3)×(﹣9)﹣(﹣5)
(3)
(4)1÷(﹣3)×(﹣
(5)
(6)
(7)(x2+2xy+y2)﹣(x2﹣xy+y2
(8)9a2﹣[7a2﹣2a﹣2(a2﹣3a)]﹣3
题型:计算题难度:中档来源:期中题

答案

解:(1﹣)﹣12+15﹣|﹣7﹣8|=﹣12+15﹣15=﹣12
(2)(﹣3)×(﹣9)﹣(﹣5)=27+5=32
(3)=(﹣+)×12=﹣10+8﹣9=﹣11
(4)1÷(﹣3)×(﹣)=1÷×=
(5)=9﹣(﹣)?﹣6?=9+=(6)
=﹣4×{[÷(﹣)﹣]÷(﹣3)}
=﹣4×[(﹣)÷(﹣3)]
=﹣4×4.7
=﹣18.8
(7)(x2+2xy+y2)﹣(x2﹣xy+y2)=x2+2xy+y2﹣x2+xy﹣y2=3xy
(8)9a2﹣[7a2﹣2a﹣2(a2﹣3a)]﹣3=9a2﹣7a2+2a+2a2﹣6a﹣3=4a2﹣4a﹣3

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