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> 已知x2-y2=xy,且xy≠0,求代数式x2y-2+x-2y2的值.-数学
已知x2-y2=xy,且xy≠0,求代数式x2y-2+x-2y2的值.-数学
题目简介
已知x2-y2=xy,且xy≠0,求代数式x2y-2+x-2y2的值.-数学
题目详情
已知x
2
-y
2
=xy,且xy≠0,求代数式x
2
y
-2
+x
-2
y
2
的值.
题型:解答题
难度:中档
来源:不详
答案
∵x2-y2=xy,
∴原式=
x
2
y
2
+
y
2
x
2
=
x
4
+
y
4
x
2
y
2
=
(
x
2
-
y
2
)
2
+2
x
2
y
2
x
2
y
2
=
3
x
2
y
2
x
2
y
2
=3.
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题目简介
已知x2-y2=xy,且xy≠0,求代数式x2y-2+x-2y2的值.-数学
题目详情
答案
∴原式=
=
=
=3.