先化简,再求值.4xy-[2(x2+xy-2y2)-3(x2-2xy+y2)],其中x=-12,y=12-数学

题目简介

先化简,再求值.4xy-[2(x2+xy-2y2)-3(x2-2xy+y2)],其中x=-12,y=12-数学

题目详情

先化简,再求值.4xy-[2(x2+xy-2y2)-3(x2-2xy+y2)],其中x=-
1
2
,y=
1
2
题型:解答题难度:中档来源:不详

答案

∵4xy-[2(x2+xy-2y2)-3(x2-2xy+y2)]
=4xy-(2x2+2xy-4y2-3x2+6xy-3y2)
=x2-4xy+7y2,
∴当x=-class="stub"1
2
,y=class="stub"1
2
时,
原式=x2-4xy+7y2=(-class="stub"1
2
)2-4×(-class="stub"1
2
)×class="stub"1
2
+7×(class="stub"1
2
)2=class="stub"1
4
+1+class="stub"7
4
=3.

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