化简下列各式:(1)(a+1a-1+1a2-2a+1)÷aa-1.(2)(-1)2010-(3-2)0+(12)-1.-数学

题目简介

化简下列各式:(1)(a+1a-1+1a2-2a+1)÷aa-1.(2)(-1)2010-(3-2)0+(12)-1.-数学

题目详情

化简下列各式:
(1)(
a+1
a-1
+
1
a2-2a+1
a
a-1

(2)(-1)2010-(
3
-
2
)0+(
1
2
)-1
题型:解答题难度:中档来源:不详

答案

(1)原式=[class="stub"a+1
a-1
+class="stub"1
(a-1)2
]•class="stub"a-1
a
=
a2-1+1
(a-1)2
class="stub"a-1
a
=
a2
(a-1)2
class="stub"a-1
a
=class="stub"a
a-1

(2)原式=1-1+2=2.

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