(1)x-x2-y2x+x2+y2x-y;(2)2x-1y-1(x+y)x-1+y-1.-数学

题目简介

(1)x-x2-y2x+x2+y2x-y;(2)2x-1y-1(x+y)x-1+y-1.-数学

题目详情

(1)x-
x2-y2
x
+
x2+y2
x
-y;
(2)
2x-1y-1(x+y)
x-1+y-1
题型:解答题难度:中档来源:不详

答案

(1)原式=(x-y)-(
x2-y2
x
-
x2+y2
x

=(x-y)-
-2y2
x

=class="stub"x-y
x
-
-2y2
x

=
x2-xy+2y2
x


(2)原式=
2(x+y)
xy
class="stub"1
x
+class="stub"1
y

=
2(x+y)
xy
class="stub"y+x
xy

=
2(x+y)
xy
class="stub"xy
x+y

=2.
故答案为
x2-xy+2y2
x
、2.

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