计算:(1)x-4x2-1÷(x+1)(x-4)x2+2x+1+1x-1(2)a-6a2-4-22a-a2.-数学

题目简介

计算:(1)x-4x2-1÷(x+1)(x-4)x2+2x+1+1x-1(2)a-6a2-4-22a-a2.-数学

题目详情

计算:
(1)
x-4
x2-1
÷
(x+1)(x-4)
x2+2x+1
+
1
x-1

(2)
a-6
a2-4
-
2
2a-a2
题型:解答题难度:中档来源:不详

答案

①原式=class="stub"x-4
(x-1)(x+1)
(x+1)2
(x+1)(x-4)
+class="stub"1
x-1

=class="stub"1
x-1
+class="stub"1
x-1

=class="stub"2
x-1

②原式=class="stub"a-6
(a-2)(a+2)
-class="stub"2
a(2-a)

=class="stub"a-6
(a-2)(a+2)
+class="stub"2
a(a-2)

=
a2-6a
a(a-2)(a+2)
+class="stub"2a+4
a(a-2)(a+2)

=
a2-4a+4
a(a-2)(a+2)

=
(a-2)2
a(a-2)(a+2)

=class="stub"a-2
a(a+2)

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