一项工程甲20天做完,乙12天做完,丙10天做完,实际为三人合作天数都为整数,甲丙共计做了13天,求乙做的天数.-数学

题目简介

一项工程甲20天做完,乙12天做完,丙10天做完,实际为三人合作天数都为整数,甲丙共计做了13天,求乙做的天数.-数学

题目详情

一项工程甲20天做完,乙12天做完,丙10天做完,实际为三人合作天数都为整数,甲丙共计做了13天,求乙做的天数.
题型:解答题难度:中档来源:不详

答案

当甲做12天,丙做1天时,
乙做了:
(1-class="stub"1
20
×
12-class="stub"1
10
)÷class="stub"1
12

=(1-class="stub"3
5
-class="stub"1
10
÷class="stub"1
12

=class="stub"3
10
÷class="stub"1
12

=3.6(天),
当甲做11天,丙做2天时,
乙做了:
(1-class="stub"1
20
×11-class="stub"1
10
×
2)÷class="stub"1
12

=(1-class="stub"11
20
-class="stub"1
5
÷class="stub"1
12

=class="stub"1
4
÷class="stub"1
12

=3(天),
当甲做10天,丙做3天时,
乙做了:
(1-class="stub"1
20
×
10-class="stub"1
10
×
3)÷class="stub"1
12

=(1-class="stub"1
2
-class="stub"3
10
÷class="stub"1
12

=class="stub"1
5
÷class="stub"1
12

=2.4(天),
当甲做9天,丙做4天时,
乙做了:
(1-class="stub"1
20
×
9-class="stub"1
10
×
4)÷class="stub"1
12

=(1-class="stub"9
20
-class="stub"2
5
÷class="stub"1
12

=class="stub"3
20
÷class="stub"1
12

=1.8(天),
当甲做8天,丙做5天时,
乙做了:
(1-class="stub"1
20
×
8-class="stub"1
10
×
5)÷class="stub"1
12

=(1-class="stub"2
5
-class="stub"1
2
÷class="stub"1
12

=class="stub"1
10
÷class="stub"1
12

=1.2(天),
因乙做的天数是整数天,故乙做了3天,
答:乙做了3天.

更多内容推荐