for months to look for a job as a bank clerk, Smith finally took a position at a local advertisinga

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• 将x=23代入反比例函数y=-1x中，所得函数记为y1，又将x=y1+1代入函数中，所得函数记为y2，再持x=y2+1代入函数中，所得函数记为y3，如此继续下去，则y2009值为（）A．2B．-13C
• 如图，在平面直角坐标系中，矩形OEFG的顶点F的坐标为（4，2），将矩形OEFG绕点O逆时针旋转，使点F落在y轴上，得到矩形OMNP，OM与GF相交于点A．若经过点A的反比例函数(x＞0)的图象-九年
• 如图，矩形OABC放置在第一象限内，已知A(3，0)，∠AOB＝30°，反比例函数y＝的图像交BC、AB于点D、E．(1)若点D为BC的中点，试证明点E为AB的中点；(2)若点A关于直线OB的对称点为
• 如图，点A在反比例函数y＝(x>0)的图像上，点B在反比例函数y＝－(x<0)的图像上，且∠AOB＝90°，则tan∠OAB（）．A．B．C．D．-九年级数学
• 已知点(－1，y1)、(2，y2)、(3，y3)在反比例函数的图象上．下列结论中正确的是A．y1>y2>y3B．y1>y3>y2C．y3>y1>y2D．y2>
• 反比例函数y1=，y2=（k≠0）在第一象限的图象如图，过y1上的任意一点A，作x轴的平行线交y2于点B，交y轴于点C，若S△AOB=2，则k=_________．-九年级数学
• 若点(，)在反比例函数的图象上，则k=。-九年级数学
• 反比例函数的图象如图所示，以下结论：①常数；②当时，函数值；③随的增大而减小；④若点在此函数图象上，则点也在此函数图象上.其中正确的是（）A．①②③④B．①②③C．①②④D．②③④-九年级数学
• 已知反比例函数y=（k＜0）的图象上有两点A（x1，y1），B（x2，y2），且x1＜x2，则y1﹣y2的值是（）．A．正数B．负数C．非正数D．不能确定-九年级数学
• 已知反比例函数的图象经过点（a，b），则它的图象也一定经过（）A．（－a，－b）B．（a，－b）C．（－a，b）D．（0，0）-九年级数学
• 如图，已知双曲线(x>0)，(x>0),点P为双曲线上的一点，且PA⊥x轴于点A，PA、PO分别交双曲线于B、C两点，则△PAC的面积为()A.1B.1.5C.2D.3-九年级数学
• 已知k1＜0＜k2，则函数和的图象大致是A．B．C．D．-八年级数学
• 李老师开车从甲地到相距240千米的乙地，如果邮箱剩余油量y（升）与行驶里程x（千米）之间是一次函数关系，其图像如图所示，那么到达乙地时邮箱剩余油量是升．-八年级数学
• （2013年浙江义乌3分）已知两点P1（x1，y1）、P2（x2，y2）在反比例函数的图象上，当x1＞x2＞0时，下列结论正确的是【】A．0＜y1＜y2B．0＜y2＜y1C．y1＜y2＜0D．y2＜y
• 若反比例函数的图象经过点（﹣2，m），则m的值是A．B．C．D．-八年级数学
• 反比例函数y=的图象经过点（﹣2，3），则k的值为．-八年级数学
• 在反比例函数图象的每一支曲线上，y都随x的增大而减小，则k的取值范围是A．k＞3B．k＞0C．k＜3D．k＜0-九年级数学
• 已知：如图，双曲线的图象经过A（1，2）、B（2，b）两点．（1）求双曲线的解析式；（2）当1<x<2时，反比例函数函数值的取值范围．-八年级数学
• 如图，在直角坐标系中，点是轴正半轴上的一个定点，点是双曲线（）上的一个动点，当点的横坐标逐渐增大时，的面积将会（）A．逐渐增大B．不变C．逐渐减小D．先增大后减小-八年级数学
• 已知反比例函数y=(k≠0)经过（1，-3），则k=.-九年级数学