化简或先化简后求值①x2+2x+3(x2-23x)②已知|a+3|+(b-12)2=0,求代数式(2a2b+2ab2)-[2(a2b-1)+3ab2+2]的值.-数学

题目简介

化简或先化简后求值①x2+2x+3(x2-23x)②已知|a+3|+(b-12)2=0,求代数式(2a2b+2ab2)-[2(a2b-1)+3ab2+2]的值.-数学

题目详情

化简或先化简后求值
①x2+2x+3(x2-
2
3
x)
②已知|a+3|+(b-
1
2
2=0,求代数式(2a2b+2ab2)-[2(a2b-1)+3ab2+2]的值.
题型:解答题难度:中档来源:不详

答案

①原式=x2+2x+3x2-2x
=4x2;

②∵|a+3|+(b-class="stub"1
2
)2=0,
∴a+3=0,b-class="stub"1
2
=0,
解得:a=-3,b=class="stub"1
2

原式=2a2b+2ab2-2a2b+2-3ab2-2
=-ab2
=-(-3)×class="stub"1
4

=class="stub"3
4

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