如图,△A1A2B是直角三角形,∠A1A2B=90°,且A1A2=A2B=4,A2A3⊥A1B,垂足为A3,A3A4⊥A2B,垂足为A4,A4A5⊥A3B,垂足为A5,A5A6⊥A4B,垂足为A6,…

题目简介

如图,△A1A2B是直角三角形,∠A1A2B=90°,且A1A2=A2B=4,A2A3⊥A1B,垂足为A3,A3A4⊥A2B,垂足为A4,A4A5⊥A3B,垂足为A5,A5A6⊥A4B,垂足为A6,…

题目详情

如图,△A1A2B是直角三角形,∠A1A2B=90°,且A1A2=A2B=4,A2A3⊥A1B,垂足为A3,A3A4⊥A2B,垂足为A4,A4A5⊥A3B,垂足为A5,A5A6⊥A4B,垂足为A6,…以此类推,则线段A2nA2n+1(n为正整数)的长为______.
题型:填空题难度:偏易来源:不详

答案

∵∠A1A2B=90°,A1A2=A2B=4,A2A3⊥A1B,
∴A2A3=
2
2
A1A2=
2
2
×4=2
2

∵A3A4⊥A2B,A4A5⊥A3B,
∴A4为A2B的中点,A5为A3B的中点,
∴A4A5=class="stub"1
2
A2A3=class="stub"1
2
×2
2
=
2
,即A2×2A2×2+1=
2

…,
以此类推,A6A7=class="stub"1
2
A4A5=
2
2
,即A2×3A2×3+1=
2
2

…,
A2nA2n+1=
2
2n-2

故答案为:
2
2n-2

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