复数z满足(1+2i).z=4+3i,则复数z=()A.2-iB.2+iC.-2-iD.-2+i-数学

题目简介

复数z满足(1+2i).z=4+3i,则复数z=()A.2-iB.2+iC.-2-iD.-2+i-数学

题目详情

复数z满足(1+2i)
.
z
=4+3i
,则复数z=(  )
A.2-iB.2+iC.-2-iD.-2+i
题型:单选题难度:中档来源:唐山二模

答案

(1+2i)
.
z
=4+3i
,得
.
z
=class="stub"4+3i
1+2i
=
(4+3i)(1-2i)
(1+2i)(1-2i)
=class="stub"10-5i
5
=2-i

所以z=
.
.
z
=2+i.
故选B.

更多内容推荐